I'm not dead, yet.
Last quarter sucked at school. This quarter is better, so far. I'm still working as much but taking fewer classes. Hopefully, I'll be a little less harried.
Oh, well. Maybe, in the fiture, I'll pass along a cute new analysis or algebra fact from class each time. Well. Next time.
----
Okay, I'll do it this time (but in linky-link form)
Consider a metric space (X, d) then let F be the set of all closed and bounded subsets of X. Now consider the Hausdorff metric on F.
Let f(x)=1/3x and g(x) = 1/3x + 2/3. Define G:F->F to be G(A) = f(A)Ug(A). Then G is a contraction. Which implies that for some set, A, in F G(A) = A. (It has a fixed point).
Taking the metric space [0,1] with the usual metric. The fixed point in this metric space is the Cantor Set.
Fun stuff.
Last quarter sucked at school. This quarter is better, so far. I'm still working as much but taking fewer classes. Hopefully, I'll be a little less harried.
Oh, well. Maybe, in the fiture, I'll pass along a cute new analysis or algebra fact from class each time. Well. Next time.
----
Okay, I'll do it this time (but in linky-link form)
Consider a metric space (X, d) then let F be the set of all closed and bounded subsets of X. Now consider the Hausdorff metric on F.
Let f(x)=1/3x and g(x) = 1/3x + 2/3. Define G:F->F to be G(A) = f(A)Ug(A). Then G is a contraction. Which implies that for some set, A, in F G(A) = A. (It has a fixed point).
Taking the metric space [0,1] with the usual metric. The fixed point in this metric space is the Cantor Set.
Fun stuff.
VIEW 3 of 3 COMMENTS
nikonphoto80:
i just need any kind of job right now, i'm going into so much debt right now.
nikonphoto80:
how goes it?