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DrStinkypants

DrStinkypants

Saint Paul, MN
October 2002

MAY 13, 2004 08:44 PM

You have a non right traingle with sides length a, b, and c. How do you find a given angle of 2 sides?

[Edited on May 13, 2004 by DrStinkypants]

SupremePizzaMan

SupremePizzaMan

Seattle, WA
September 2003

MAY 13, 2004 08:44 PM

Theyre given. You'd already have them.

radiofrank

radiofrank

Mississauga, ON
November 2002

MAY 13, 2004 08:48 PM

Ack! I remember dealing with this in math. I'm not sure it can be done without knowing at least one of the angles; if you have one then you can use either the sine or cosine law to calculate the other angle.

Okay, I rooted through some of my textbooks, and found the following. Given the sides A, B, and C, where a, b, and c are the angles opposite those sides:

Cosine Law: C^2 = A^2 + B^2 - 2ABcos(c)

Sine Law: sin(a)/A = sin(b)/B = sin(c)/C

Hope that helped. smile

[Edited on May 13, 2004 by radiofrank]

crispy

crispy

NEWSWIRE

Philadelphia, PA

MAY 13, 2004 08:55 PM

Is it given as strictly variables?

radiofrank

radiofrank

Mississauga, ON
November 2002

MAY 13, 2004 09:03 PM

crispy said:
Is it given as strictly variables?




In any text that I've ever read it has always been given as strictly variables. But that probably just means that I've read far too many math books. wink

scotty_bane

scotty_bane

Fort Worth, TX
February 2004

MAY 13, 2004 09:27 PM

awww dude you just broke my brain.

Corso

Corso

New York, NY
November 2003

MAY 13, 2004 09:33 PM

Uh, I dunno. Ask Al?

AceTracer

acetracer

Hollywood, FL
January 2004

MAY 13, 2004 09:34 PM

You know there's a group for you geeks to play in surreal

DrStinkypants

DrStinkypants

Saint Paul, MN
October 2002

MAY 14, 2004 03:21 AM

radiofrank said:
Sine Law: sin(a)/A = sin(b)/B = sin(c)/C

Hope that helped. smile

[Edited on May 13, 2004 by radiofrank]



for that law A, B, and C are sides that are opposite of angles a, b, and c, respectively. so without any angles, that formula is useless.
Since the sides are constatly proportionate to one another ther must be a way to fond the relation of the angles, i just cant fiugure it out
AHHHHHHHHHHHHHHHH!!!! I'm two steps away from becoming an art major!!!


For the rest of you, yes we do have a group, i just thought one of you civilians would have an answer smile

Al

Al

SUICIDEGIRL

Christmas Island

MAY 14, 2004 03:33 AM

DrStinkypants said:

radiofrank said:
Sine Law: sin(a)/A = sin(b)/B = sin(c)/C

Hope that helped. smile

[Edited on May 13, 2004 by radiofrank]



for that law A, B, and C are sides that are opposite of angles a, b, and c, respectively. so without any angles, that formula is useless.
Since the sides are constatly proportionate to one another ther must be a way to fond the relation of the angles, i just cant fiugure it out
AHHHHHHHHHHHHHHHH!!!! I'm two steps away from becoming an art major!!!


For the rest of you, yes we do have a group, i just thought one of you civilians would have an answer smile



Well, there's always the cosine law, which works if you have all 3 sides (and is mentioned above).